Property of an XOR:
A XOR B = AB' + A'B (produces 1 if either
A is 1 or B is 1, but not if both are 1).
So now your equation is:
A'B+(BC' + C'B)
A'B+BC'+B'C
Then with the use of K-maps, you can manipulate it to
A'C + BC' + B'C
This of course isn't any more simplified, just another option. If you have any questions let me know.