In attached circuit I want to know why there is 6.5mA of current flow in 2nd leg? Shouldn't all current flow through to leg 1 (only diode attached)?
Attachments
-
13.1 KB Views: 47
Vd2 and I2 are 2 unknowns. Lets say Vd1 = 0.7V, then how do I get Vd2?Vd1 = Vd2 + 10 x I2
That is why they provide us with simulators. Here is an alternate simulation using a free downloadable simulator, LTSpice. In this case, the diodes are simplified, ideal diodes. The results match quite closely with Falstad. Not so much if I replace D1 and D2 with 1N4000 series diodes....
Simple to say but difficult to do with any accuracy using such a poor graph as the manufacturer provides.