Discussion in 'Homework Help' started by mattm, Aug 10, 2009.

1. ### mattm Thread Starter Member

Aug 5, 2009
19
0
as far as the generator is concerned, in a series-resonant LC circuit(with no resistor), L and C can be replaced by a resistor with the same value of L x C?

2. ### mattm Thread Starter Member

Aug 5, 2009
19
0
or can you just replace it with a peice of wire?

3. ### veritas Active Member

Feb 7, 2008
167
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You need L and C for the circuit to be resonant.

4. ### t_n_k AAC Fanatic!

Mar 6, 2009
5,448
790
In part this is correct - at least at resonance in a series LC circuit the effective impedance becomes equivalent to a resistance. If L & C are ideal then the effective resistance would be zero at resonance. But just replacing L & C with a resistance does not give an equivalent circuit at all other frequencies. For instance, a series LC circuit will not pass continuous DC current, whereas a resistor will. At all other frequencies the impedance is reactive - increasingly inductive above resonance and increasingly capacitive below resonance.

5. ### JoeJester AAC Fanatic!

Apr 26, 2005
4,074
1,776
the only time I've seen replacing a series resonant circuit (antenna) with a resistor is when you connect the transceiver up to a dummy load.