I'm ashalina n new in this forum...
I've to submit an assignment of electronic tomorrow...im also new in electronic studies and my major is "Comuter and information systems"..
I do hope u guys will help me in my assignment...
Q1:Why we change Vp(peak voltage) to Vrms form in sloving problems rectifiers?
(like vp=vrms/0.707)
I need a descriptive answer...
Q2:We have 12Vac across primary coil in a bridge rectifier and resistance is given 12Kohm...what will be the dc voltage and current for this circuit?

Regards............

 

Q1:Why we change Vp(peak voltage) to Vrms form in sloving problems rectifiers?
(like vp=vrms/0.707)
I need a descriptive answer...

A descriptive answer can be easily composed after reading: http://www.allaboutcircuits.com/vol_2/chpt_1/3.html

Q2:We have 12Vac across primary coil in a bridge rectifier and resistance is given 12Kohm...what will be the dc voltage and current for this circuit?

Use the formula for converting AC. Remember that E=I*R.

 

RMS voltage is nothing more than the DC equivalent (in respect to power output). For example, 12VAC p-p is the equivalent of 4.24VDC in terms of power output. If you have two light bulbs, one with 12VAC p-p and the other with 4.24VDC, both will be the same brightness and have the same power output. Remember that RMS is calculated to include only peak to neutral, so you have to halve a p-p AC voltage when calculating RMS. Also, once you find the DC equivalent of the AC waveform, then you can use that DC equivalent to find the DC current for the circuit.