y=a'b+cd+(a'+b')(acd+b'e')

y=ABC'D'+DE'F+AF'

Y=A'(B+C'(D+E))

 

Need the diagrams asap

 

It does not work that way here. You draw the circuits, and we'll help you get it right. If we draw the circuits outright what have you learned?

I have a set of templates in my PaintCAD program so you can draw them electronically. Or you can draw them by hand and post them for critique.

 

could you please draw them for me

 

Did you miss a class? Again, we don't do your homework, but we will help you learn. What part of drawing them are you having problem with? Boolean multiplication is an AND function, + is an OR function, and the ' is inverted.

I will give you an example off an old illustration I made a while back.

The formula for this problem is

or X = A'B'D'+BC'D+AB'CD+A'B'C'

Note the AND gate correspond to the multiplication on the Boolean equation.

One of the ways you convert gates to other gates with equivalent functions is:

A good refresher on the AAC book...

http://www.allaboutcircuits.com/vol_4/chpt_7/8.html

 

y=a'b+cd+(a'+b')(acd+b'e')

y=ABC'D'+DE'F+AF'

Y=A'(B+C'(D+E))

are these correct
for the first please suggest a overall gate..
if there are any mistakes please suggest and please correct them..
thanks..

 

All your diagrams have several errors. You need to break the equation down into pieces like this...

Combine the gates you see above with this...

you should be able to simplify (and if you wish, combine) several gates.

Gates 3 and 5 can be translated to other types of gates using the above information.

 

(Bill gets 100 on this test)

 

(bowing) Thank you, Thank you (bowing again)...

I've only done one, and that is all I plan on doing. I have a feeling the OP missed a critical class somewhere. Having made the effort I'll try to show how it needs done in such a way he can pick it up.

How many panicked students have we had when they found out their professors know about this site, and read their problems posted for all to see.