The problem with this equation is that it does not account for the existence of the dependent voltage source with its value of 6i volts.i use I=V/R, I=6i/4=1.5i
(i dont understand this sentences)^^hgmjr said:Now notice that the dependent voltage source is also 6i volts and it has the same polarity as the voltage across the 6 ohm resistor. It should then be apparent that the voltage at both ends of the 4 ohm resistor in the 6 ohm case are identical. That means that the current flowing in the 4 ohm resistor is always 0 amps.
You can see that there is a dependent voltage source located at the far left and labeled with the value 6i volts. This is the voltage source I referred to in the statement above.hgmjr said:notice that the dependent voltage source is also 6i volts
Hopefully, I did a better job of explaining? If not, let me know where I have lost you and I will take another run at it.By the way, it may be easier for you to work on this problem if you temporarily replace the value of the driving current source 2*cos(2t) with say the label "I" and then once you have performed all of your calculations you can come back later and plug in the actual value to arrive at the final answer.
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by Jake Hertz
by Jake Hertz
by Aaron Carman