i can't prove this one:

AC + AB + BC' = AC + BC'

is it easy? thanks for the help!

 

It has been a real long time since I did boolean but first guess would be AB-0

I am sure I will be corrected.

 

i dunno. i just need to simplify this one but i dont know what to do with AB..
im only high school so i dont know this one. hehe..

 

Try taking a look at the information contained in the tutorial at this link.

http://www.allaboutcircuits.com/vol_4/chpt_7/3.html

What you will need to do is apply one or more boolean identites described in this tutorial.

hgmjr

 

i can't prove this one:

AC + AB + BC' = AC + BC' (1)

is it easy? thanks for the help!

Likewise it is some time since I did Boolean algebra, but here is my approach to this:

From equation (1) take out A as a common factor:

A(C+B) + BC' (2)

Now again from equation (1) take out B as a common factor:

AC + B(A+C') (3)

Equate (2) and (3):

A(C+B) + BC' = AC + B(A+C')

Where C = C+B and C' = A+C', i.e. C is independant of B and C' is independant of A

Therefore:

AC + AB + BC' = AC + BC'

Dave