I need to graph a bode plot of this transfer function
H(jω) = (1.5 x 10^-3 *(1+jω/10)) / ((1+jω/100)(1+jω/500))
and I have no idea how to do so. I'm trying to follow an example my professor did in his notes. I replace jω with an "s" so the equation looks like this
H(s) = (1.5 x 10^-3 *(1+s/10)) / ((1+s/100)(1+s/500))
It seems he graphed each component of a transfer function separately, so I'll try to do the same
Gain of 1.5 x 10^-3 is 20log(1.5 x 10^-3) = -56.5db.
It's graph is just a horizontal line at height -56.5db for all ω. The x axis is where ω is.
(1+s/10) has corner frequency at ω = 10. So it contributes 20db/decade asymptote started at ω=10.
(1+s/100) has corner frequency at ω = 100. Since it is in the denominator, it contributes -20db/decade asymptote started at ω=100.
(1+s/500) has corner frequency at ω = 500. Since it is in the denominator, it contributes -20db/decade asymptote started at ω=500.
Now how do I physically add all the plots to give me an overall bode plot?
H(jω) = (1.5 x 10^-3 *(1+jω/10)) / ((1+jω/100)(1+jω/500))
and I have no idea how to do so. I'm trying to follow an example my professor did in his notes. I replace jω with an "s" so the equation looks like this
H(s) = (1.5 x 10^-3 *(1+s/10)) / ((1+s/100)(1+s/500))
It seems he graphed each component of a transfer function separately, so I'll try to do the same
Gain of 1.5 x 10^-3 is 20log(1.5 x 10^-3) = -56.5db.
It's graph is just a horizontal line at height -56.5db for all ω. The x axis is where ω is.
(1+s/10) has corner frequency at ω = 10. So it contributes 20db/decade asymptote started at ω=10.
(1+s/100) has corner frequency at ω = 100. Since it is in the denominator, it contributes -20db/decade asymptote started at ω=100.
(1+s/500) has corner frequency at ω = 500. Since it is in the denominator, it contributes -20db/decade asymptote started at ω=500.
Now how do I physically add all the plots to give me an overall bode plot?