attached is the problem, here is what I did and the answer I got.
Because the current supply produces 50 watts we know it is producing 10 volts. also we know that 5 amps across 4 ohms is a drain of 20 volts, thus we have 10 volts at the node between the two 4 ohm resisters. Then using KCL going into that node we have (0v 10v)/2 ohms [from ground to node]+ (5v 10v)/4 ohms [from 5 volt source to node) + 5 amps [from 5 amp source] = 13.75 amps. Now Vx=2 ohms * the current found =27.5 v
The correct answer is suppose to be 42.5 v So I ask you what have I done wrong?
thanks
Because the current supply produces 50 watts we know it is producing 10 volts. also we know that 5 amps across 4 ohms is a drain of 20 volts, thus we have 10 volts at the node between the two 4 ohm resisters. Then using KCL going into that node we have (0v 10v)/2 ohms [from ground to node]+ (5v 10v)/4 ohms [from 5 volt source to node) + 5 amps [from 5 amp source] = 13.75 amps. Now Vx=2 ohms * the current found =27.5 v
The correct answer is suppose to be 42.5 v So I ask you what have I done wrong?
thanks
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