Hello! Need some help with my homework. Can you help me in guiding me with the answer to this equation(need R3 Ω value):



thanks in advance!!!

 

Is A in a circle a current source?

 

Current source? No. A(for amps) is simply measuring the current on that circuit.

V = 100
I(t) = 10A
R1 = resistor using 500w
R2 = resistor using 100w (in parallel with R3)
R3 = resistor using ?w (in parallel with R2)
Need ohms value of R3

Is A in a circle a current source?

 

Current source? No. A(for amps) is simply measuring the current on that circuit.

V = 100
I(t) = 10A
R1 = resistor using 500w
R2 = resistor using 100w (in parallel with R3)
R3 = resistor using ?w (in parallel with R2)
Need ohms value of R3

Ok. So total power provided to the circuit is P=100*10=1000 W.

R1 consumes 500 W.
R2 consumes 100 W.
That accounts for 500+100=600 W.

That leaves R3, R3 must consume the rest, 1000-600=400 W.
The voltage across R3 is same as the voltage across R2. So. Find voltage across R2, then plug it into the formula for power for R3, that will allow you to find resistance of R3.

 

You know your total WATTS using 100V and 10 Amps by using Ohms law I*V, and you are able to determine total resistance by using Ohms law V/I.

This will give you the WATTS in R3 and the ratio of R1, R2, and R3.

This should be enough to get you the answer.

 

Isn't there a voltage drop after R1? Trying to calculate the ohms value of R1 from watts. Is the value of R1 10 ohms? 100V divided by 10A = 10 ohms. But the voltage drop....stuck on that.

 

Isn't there a voltage drop after R1? Trying to calculate the ohms value of R1 from watts. Is the value of R1 10 ohms? 100V divided by 10A = 10 ohms. But the voltage drop....stuck on that.

You know the current through R1, it is 10 A.
You know the power at R1.
For R1: 500 W= (10 A)(V across R1)
Solve for V across R1.

 

Ok, so R1 = 5Ω and R2 = 1Ω Am I correct?

 

Ok, so R1 = 5Ω and R2 = 1Ω Am I correct?

R1 is 5 Ohm.

R2 is not 1 Ohm because before you get to R2 the current is split into two. So some part of 10 A goes through R2, another part of 10 A goes through R3.

The bottom line is that we don't give a damn about resistance and current through R2. The only thing we want from R2 is the voltage across R2. The voltage across R2 is 100 V minus Voltage across R1. Which also means that we don't give a damn about resistance of R1. So why the eF are you wasting your time on figuring out that R1 is 5 Ohm?

 

Ok, so if R1 is 500w, and the current is 10a, (V=W/I) then we're looking at 50v at R1.

Now, since the current is divided into 2 before R2 and R3, and R2 is 100w consumption, how do I figure out the resistance of R3?

R1 is 5 Ohm.

R2 is not 1 Ohm because before you get to R2 the current is split into two. So some part of 10 A goes through R2, another part of 10 A goes through R3.

The bottom line is that we don't give a damn about resistance and current through R2. The only thing we want from R2 is the voltage across R2. The voltage across R2 is 100 V minus Voltage across R1. Which also means that we don't give a damn about resistance of R1. So why the eF are you wasting your time on figuring out that R1 is 5 Ohm?

 

Ok, so if R1 is 500w, and the current is 10a, (V=W/I) then we're looking at 50v at R1.

Now, since the current is divided into 2 before R2 and R3, and R2 is 100w consumption, how do I figure out the resistance of R3?

Simple. I told you how to find Power at R3. I told you how to find Voltage at R3. All you have to do now is to solve for resistance of R3.

Power=(V^2)/R
Power is known.
V is known.
Solve for R.

 

I think I got it. 50v supplied down to R2 and R3 and if R3 was 400w, then the resistance is 6.25Ω

 

Yep.