# help-boolean algebra

#### mira

Joined Jun 28, 2007
3
hi, guys....i need some help with these question...i will be grateful if u could help me...

simplification using boolean algebra only..

A) F1 = w'x' + (w'x')'

b) F2 = w(w + w'xy)

c) F3 = xy(v.v')

d) F4 = (v + (wy)')'

e) F(v,w,x,y) = F1+F2+F3+F4

#### mira

Joined Jun 28, 2007
3
i have tried to do them not sure if they r right?
w'x' + (w'x')'
=w'x' + wx

#### electroperk

Joined Jun 30, 2007
8
if ' means bar then solution might be

f1=w'x'+(w'x')'
for this now let w'x' be a then
f1=a+a' that is f1=1;
let me explain this
suppose a=1 then a'=0 in this case f1=1;
and if a=0 then a'=1 in this case also f1=1;
hence f1=1 always...

now going for f2=w(w+w'xy)
or f2=ww+ww'xy and as ww=w and ww'=0 always
therefore f2=w....

now f3=x.y(v.v') then v.v'=0....
therefore f3=0....

now F4 = (v + (wy)')'
using de'morgans law
f4=(v+w'+y')'..
and again we will use de'morgans law..
f4=v'wy..

therefore..

F(v,w,x,y) = F1+F2+F3+F4=1+ w+0+v'wy..

i think i have tried my level best...

#### mira

Joined Jun 28, 2007
3
thanks alot for the help...really appreciate...

#### daveglion

Joined Jul 1, 2007
21
wow! boolean algebra!! need ko po ng tutorial dyan assignment ko po kasi eh... pls post naman po ng link about boolean
ty po...