In my text for example problem it asks:
An 8.2V zener diode ( 8.2V at 25°C ) has a positive temperature coefficient of 0.05%/°C. What is the zener voltage at 60°C?
Solution:
The change in zener voltage is ΔVz = Vz*TC*ΔT
( 8.2V)(0.05%/°C)(60°C - 25°C) = ( 8.2V )(0.0005/°C )( 60°C - 25°C )= 144mV.
My question is why does the 0.05%/°C change to 0.0005/°C?

Thanks in advance.

 

It doesn't change, 0.05% is defined as 0.0005, that's how percentages work.
1% = 0.01

 

It doesn't change, 0.05% is defined as 0.0005, that's how percentages work.
1% = 0.01

ah...got it, don't know why I didn't see that. Thanks