What parameters are required in order to describe a sine wave?I don't understand were you get any values from to work out the average.
Yes I can do Calculus.
What parameters are required in order to describe a sine wave?I don't understand were you get any values from to work out the average.
Yes I can do Calculus.
Yes they told me to use Multism but I am waiting for the tutor to come back to me with activation codes etc, as they aren't working.I would recommend LTSpice but the learning curve is steep. I think it would distract from the problem at hand. Doesn't your school use a software tool such as Multisim?
https://www.analog.com/en/design-center/design-tools-and-calculators/ltspice-simulator.html#
You get the values from the trace and the given parameter for the circuit.
Amplitude, cycles, frequency, peak to peak and RMS?What parameters are required in order to describe a sine wave?
You only need two. The rest are redundant. (Sometimes you need phase angle but this is unimportant in your case.)Amplitude, cycles, frequency, peak to peak and RMS?
The only figures I can see on the diagram is 5 V pk and 1KHz.You only need two. The rest are redundant. (Sometimes you need phase angle but this is unimportant in your case.)
(You may also need DC offset. But let's ignore that too.)
Let's cut the chase (to avoid playing the game of 101 Q & A).
All you need is amplitude and frequency.
You can derive RMS and peak-to-peak from amplitude.
Which of the three values, amplitude, RMS, peak-to-peak do you know for both input and output waveforms?
Where did that equation come from?Ok thanks everyone. To work out the average value of the input and output signal would you use this equation...
View attachment 200318
Many thanks
What is the input voltage as a function of time. Assume that the waveform is at 0 V at t=0.I don't understand were you get any values from to work out the average.
Yes I can do Calculus.
For a sine wave symmetrical about 0V the peak voltage is the same as its amplitude.The only figures I can see on the diagram is 5 V pk and 1KHz.
So if the voltage is the same as the amplitude then it will be 5?For a sine wave symmetrical about 0V the peak voltage is the same as its amplitude.
Intuitively, what is the average value of such a sine wave of 5V amplitude.
If the peak to peak voltage is ten volts, then the peak voltage will be 5 volts, the average will be less, likewise the RMS value and the DC equivalent is someplace in between.So if the voltage is the same as the amplitude then it will be 5?
Try again.So if the voltage is the same as the amplitude then it will be 5?