Half Wave Rectifier Problem

Discussion in 'Homework Help' started by unlisted, Jan 28, 2007.

  1. unlisted

    Thread Starter Member

    Jan 20, 2007
    The problem is a half-wave rectifier with a 1k-ohm load operates from 120V rms 60Hz through 10 to 1 step down transformer. The diode has constant voltage drop of .7 V for any current.
    Find peak voltage of rectified output.

    The AC voltage is stepped down to 120/10 = 12V rms

    The peak rectified output voltage should be 12 - .7 = 11.3V. The answer given is 16.27V. Can someone please point me in the right direction?

  2. kone

    New Member

    Nov 19, 2006
    as far as I know you must use the peak voltage not the RMS voltage to calcuate the peak rectified output.

    find peak voltage first : 12V * square root of 2 (1.41421356) = 16. 97V

    Then find peak voltage of rectified output

    16.97 - .7 = 16.27V

    I hope this makes sense?