Graphing the Trigonometric Fourier spectra

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Discussion in 'Homework Help' started by nyasha, Oct 27, 2011.

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  1. Oct 27, 2011 #1
    nyasha

    Thread Starter Active Member

    Mar 23, 2009
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    So l just need to be pointed in the right direction and the rest l will do myself. How do l get the amplitude and phase for ω=2t. There is a sine and cosine with ω=2t. How do l deal with them.
     
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  2. Oct 27, 2011 #2
    chrisw1990

    Active Member

    Oct 22, 2011
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  3. Oct 27, 2011 #3
    nyasha

    Thread Starter Active Member

    Mar 23, 2009
    90
    2

    I do understand how to get the Fourier series. The given signal is a already a calculated fourier series they just want it to sketch its Fourier spectra. I am confused on what to do at ω=2t
     
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  4. Oct 27, 2011 #4
    MrChips

    Moderator

    Oct 2, 2009
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    You probably meant to say at ω=2.

    The amplitude would be the square-root of the sum of squares:

    <br /> \sqrt{(\sqrt{3})^2 + 1^2} = \sqrt{4} = 2<br />

    See if you can figure out the phase on your own.
     
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  5. Oct 27, 2011 #5
    nyasha

    Thread Starter Active Member

    Mar 23, 2009
    90
    2
    And the phase is 30 degrees. I now get it. Thanks man.
     
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  6. Oct 27, 2011 #6
    MrChips

    Moderator

    Oct 2, 2009
    15,978
    4,879
    Well the phase angle is either 30 or 60 degrees. Try to figure out which is the correct answer.
     
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