yes , that is right , but the law as stated by gauss uses the displacement vector because it isOriginally posted by haditya@Oct 28 2004, 06:47 PM
Gauss law states that the product of electric flux and permitivity of the medium thru any surface is equal to the charge enclosed by the surface.
(phi)=flux thru the surface
in oredr to apply gauss law any"closed" suface(often referred to as gaussian surface) can be used... but we generally prefer to use surfaces that hav a certain symmetry in order to enable easy calcuation..
if u can be more specific about the problem u are havin with the application of gauss theorem...i can probably help u out.
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