Hi all.
I have 3 quite fundemental questions, which I think I know the answer of. Please correct me when/where I am wrong:
1: When looking at a coaxial cable which just ends at point x = L (no termination, so the resistance is infinite), then we have that the current satisfies I(L,t)=0. Does this mean that at the end of the cable, it looks like this? (Look at the attached image)
2: On an Ohm-meter, I can turn the "wheel" to 2 Ω, 20 Ω, 0.2 kΩ, 2 kΩ, 20 kΩ, 200 kΩ and so forth. Lets say that it is placed at 2 kΩ, and the display of the meter shows 3.02. Does this mean that the resistance is 3020 Ω? And likewise, if the "wheel" is placed at 200 kΩ, and the display shows 4.87; does this mean that the resistance is 4870 Ω?
3: Why does it say 2 Ω, 20 Ω, ... and not 1 Ω, 10 Ω, ...? (This I don't have any attempt on)
Thanks in advance. I really appreciate you helping me.
Best regards,
Niles.
I have 3 quite fundemental questions, which I think I know the answer of. Please correct me when/where I am wrong:
1: When looking at a coaxial cable which just ends at point x = L (no termination, so the resistance is infinite), then we have that the current satisfies I(L,t)=0. Does this mean that at the end of the cable, it looks like this? (Look at the attached image)
2: On an Ohm-meter, I can turn the "wheel" to 2 Ω, 20 Ω, 0.2 kΩ, 2 kΩ, 20 kΩ, 200 kΩ and so forth. Lets say that it is placed at 2 kΩ, and the display of the meter shows 3.02. Does this mean that the resistance is 3020 Ω? And likewise, if the "wheel" is placed at 200 kΩ, and the display shows 4.87; does this mean that the resistance is 4870 Ω?
3: Why does it say 2 Ω, 20 Ω, ... and not 1 Ω, 10 Ω, ...? (This I don't have any attempt on)
Thanks in advance. I really appreciate you helping me.
Best regards,
Niles.
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