I have a homework question that is confusing me.

I have to design a full wave bridge rectifier with the given the following,

-1 phase rectifier

-Voltage Source (Vs) = 230V, 50Hz

-Transformer = 230V/115V, 1.5kVA

-Ripple Factor = 3%

-All components can be considered ideal (no voltage drop across diodes)

a) Average voltage across the load

b) average current supplied to the load

c) load Resistance (neglecting ripple)

d)min filter capacitance required at rectifier output

and some more stuff

What I figure so far,

Vs----->Transformer------------>Rectifier------------>Resistive Load//Capacitor

230V-->230>/115V, 1.5kVA---->103.5V,(300/23)A-->7.935ohm//?

The output voltage from the rectifier Vd = 0.9 x Vs = 0.9 x 115 = 103.5V

Is = S/V = 1.5kVA/115V = (300/23)A

R = V/I = 103.5/(300/23) = 7.935 ohm

My confusion is weather my calculations are rms or average (dc) values.

I have also been having difficulty finding the relevant formulas for this type of rectifier.

From what I understand, the voltage after the rectifier is dc, which is why Vs is multiplied by 0.9. This is confusing because I thought dc voltage should be o.636 times the peak voltage...maybe I skipped a step somewhere???

I have the same kind of problem with my average current.

thanks guys