Full wave rectifier:the function f(t)=AsinΩt.

0 pi 2pi 3pi
timeperiod T=pi.
Ω=2pi/T=2pi/pi=2
Thereforef(t)=Asin2t. if i tried with this function a0,an,bn is zero in fourier series.But if i tried with the function f(t)=Asint i get the following series:
f(t)=2A/pi+4A/pisummation of(cos2nt/1-4npow(2))
i.e.a0=2A/pi an=4a/pi(1-4nsquare)
Which one is a right procedure?

 

Hi.

The method of solution is to first state that the function can be described by:

Asin(t) for 0 < t < pi
and
-Asin(t) for -pi < t < 0

Therefore the function has a period of 2pi, so omega is 1.