Fourier series help

Discussion in 'Homework Help' started by testing12, Jan 13, 2013.

  1. testing12

    Thread Starter Member

    Jan 30, 2011
    Can Someone please elaborate. I dont see how this can be true with the bound being 1 to 3. [​IMG]
  2. WBahn


    Mar 31, 2012
    What are you getting that the answer should be?

    Is the 1/(2π) really only multiplying the first integral?

    Note that 'π' is pi. It may or may not look much like it on your machine. On mine, it's really easy to mistake it for 'n'.

    If so, I get that the answer given should be multiplied by (4 + 1/π). If it is multiplying both integrals, then I get that it should be multiplied by (2/π). But I did the integrals really quickly, so I could have a mistake somewhere.