I want to divide a 16bit number by 8 bit number in hex format

If anyone has an idea please let me know

I tried the following link but didn't get the result

http://www.piclist.com/techref/microchip/math/div/index.htm

 

If you post the code you tried, people will be able to give more help.

 

This doesn't sound like floating point. Dividing a 16 bit quantity by an 8 bit one?

 

I used the following division subroutine

LOOP501:
 
RLF AARGB1, F ;and shift in next bit of result///////AARGB1:AARGB0 16 bit dividend
RLF AARGB0, F
RLF REMB0, F
RLF count301, F ;save carry in counter////////////count301 is initialised to 16
 
MOVF count209, W ///////count209 is the 8 bit divisor
BTFSS CARRY
INCFSZ count209, W
SUBWF REMB0, W ;keep that byte in W untill we make sure about borrow
SKPNC ;if no borrow
BSF count301, 0 ;set bit 0 of counter (saved carry)
BTFSC count301, 0 ;if no borrow
GOTO UOK46LL ;jump
MOVF REMB0, W ;read high byte of remainder to W
;to not change it by next instruction
UOK46LL
MOVWF REMB0 ;store high byte of remainder
bcf CARRY ;copy bit 0 to carry
RRF count301, F ;and restore counter
DECFSZ count301, f ;decrement counter
GOTO LOOP501 ;and repeat loop if not zero
 
 
RLF AARGB1, F 
RLF AARGB0, F
RETURN

 

If you don't need need top speed a very simple and reliable way is by successive subtraction, (it's simpler than it sounds) you just keep subtracting the 8bit number until it's done. And count the number of subtractions.

// example; 1000 / 20
i = 1000;
result = 0;
while(i >= 20)
{
  i -= 20;
  result ++;
}
// when it gets to here you have the result