Hi there, problem sorted many thanks
Upto here I've seen where I was wrong and understand. Although I dont understand how you managed to get those values for i1 and i2?... the long line in the voltage source symbols represents the positive end, and you assume a current of i1 in the left-hand loop, and a current of i2 in the right hand loop, both flowing clockwise, I get i1=5.3167 amps and i2 = 4.7778 amps. From this you can compute the output voltage of the circuit as 12.933 volts. So the Thevenin equivalent at terminals A and B is a 12.933 volt source in series with 1.499 ohms. This might even be correct if my assumption about the polarity of the voltage source symbols is right.
by Duane Benson
by Duane Benson
by Duane Benson
by Aaron Carman