Let the following transfert function : \( C(p) = 0.5926 \frac{1+1.205p}{1+0.4233p} = K \frac{1+a \cdot \tau p}{1 +p \cdot \tau p}\) with \( a = 2.848, \tau = 0.4233, K = 0.5926 \) the marge of phase of this corrector is 28.7° i want to find the cutoff frequency of this correct, the answer was already given to be 0.648 rad/sec, but i want to know how did they get it, infinite thanks!