Vbe - Vcc + (Ic + Ib)Rc + IbRb = 0
sinc Ic >> Ib we can simplify to
Vbe - Vcc + IcRc + IbRb = 0
because Ib = Ic/beta we can solve for Ic to get
Ic = (Vcc - Vbe) / (Rc + Rb/beta)
Did the problem statement include an assumed \(\beta\) for the transistor or any other transistor parameters?Hi there,
Can anyone pls kindly help me with finding Q point of the BJT in the following attachment? Thanks for your help.
by Aaron Carman
by Duane Benson
by Jake Hertz