No 50% duty is all I need. It says positive square wave. I forgot to mention that it is a +/- square wave equally bipolar. So if it was 10Vpp, it would be +5, -5V...if that makes sense.For a square-wave, RMS is the peak voltage.
Or do you need it for duty cycles other than 50%?
ETA: RMS - Peak Calculator for different waves
The reading of a multimeter is RMS, but since it's meant to give the RMS value of a sine wave, wouldn't it screw something up when its a square wave?and hence the peak-to-peak voltage would be twice the RMS reading.
The reading of a multimeter is RMS, but since it's meant to give the RMS value of a sine wave, wouldn't it screw something up when its a square wave?
http://www.amprobe.com/amprobe/usen/Multimeters/Industrial-Multimeters-/AM-270.htm?PID=73125If the meter is TRUE - RMS and marked that way, then it will give you the correct RMS voltage of any waveform (up to the frequency ability of the meter)
If the meter cost under $40-$50 or so, it is probably only True RMS for sinewaves, and the actual voltage of a different waveform is anybody's guess in the case of an Sine RMS only meter.
I got the first part about the heating. (Actually learned that in school!). Second part not so much..Let's see. I'll read it again.The RMS value is what constant DC voltage will give the same heating effect as the signal of arbitrary wave form. Hence mathematically, you have to compute the integral of the square of the amplitude and then take the square root. So when you square the negative portion, it is the same value as the positive part. Hence the RMS is the same as if the square wave was a constant DC signal.
Be careful. Most modern "true RMS meters" do some kind of integral approxination and are only accurate on signals with a crest factor less than 3. The phrase "True RMS" must be taken with a grain of salt, unless it is a thermal meter and they are rare and very expensive.Hello,
How can I find the peak-to-peak voltage of a square wave produced by a function generator when I only have a True-RMS multimeter?
I'm new at this so if someone could dumb it down for me, I'd appreciate it.
Is it possible? Thanks.
The crest factor of a square-wave is 1, so that should not be a problem for the meter.Be careful. Most modern "true RMS meters" do some kind of integral approxination and are only accurate on signals with a crest factor less than 3. The phrase "True RMS" must be taken with a grain of salt, unless it is a thermal meter and they are rare and very expensive.
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