Hi.

I am trying to figure out if I'm wrong or the given answer is wrong.

I am to solve for

*using the principle of superposition in figure 1.2.*

**I**This is my methodology:

Set all voltage sources=0.

Turn on right side voltage source. Circuit reduces to 12V voltage source and 4k resistance since the 6k is shorted.

**I is in the opposite direction to voltage.**

V=IR==> I=V/R = 12V/4k=

**3mA**(Now here the answer says -3mA but that would only happen when I and V are in the same direction no?)

Set all voltage sources=0.

Turn on left side voltage source. Circuit reduces to 12V voltage source and 6k resistance.

**This time I is in the same direction as V.**

V=IR==> I=V/R = -12V/6k=

**-2mA**(here the answer is given as 2mA but again, this would only happen when I and V are in opposite directions, no?)

Therefore by principle of superposition

**I=[3+(-2)]mA= 1mA (But answer is -1mA)**

Is there anything I'm missing or is the answer wrong? (I am inclined to believe the answer is not wrong as it was given in the mark scheme of an exam)