Source charge? Do you mean the "charge" creating the force?Revered members,
Electric potential is defined as the work done in moving a test charge from one point to other against the electric force. Usually the test charge is unit positive charge. What about the magnitude of the source charge?
This is indeed the traditional definition of a test particle, but the distinction turns out to not be critical from a practical point of view. While a large test particle does disturb the net field from the point of view of an external observer, it does not disturb the net field that effects it's own motion, or it's own net force (at least for a fixed field due to fixed charges). The reason is that the particle can not place a net force on itself. Hence, the field contribution from the particle does not come into play in a measurable way, as far as the test particle is concerned. The original field is still present and it is the only field that can affect the particle in terms of measurements an experimentalist might do to determine the original field value.The test charge should be imagined as approaching zero, else its position and charge will change the fields already present.
Then, as long as the force, or function describing the force, at the point of interest is given, the charge creating that force is of no importance. On the other hand, if the 'source' charge is fully described, one could calculate the resulting field and determine the force at the point of interest from that. However, in that case, the 'charge' is already given.Yes, Mr.BillO
Now i have two points with charge +1C and +3C. Can this termed as potential difference? Because both are positive, i get this doubt.
But in the case of statics you could construct the field and use maxwell's equation to fine the charge density ( divergence of field I think ).Then, as long as the force, or function describing the force, at the point of interest is given, the charge creating that force is of no importance. On the other hand, if the 'source' charge is fully described, one could calculate the resulting field and determine the force at the point of interest from that. However, in that case, the 'charge' is already given.
Generally, it would be difficult, or nearly impossible, to determine the source charge from only the function describing the force.
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by Jake Hertz
by Jake Hertz