Q) A harmonic time-dependent electromagnetic plane wave, of angular frequency ω, propagates along the positive z-direction in a source-free medium with σ = 0, ε = 1 and µ = 3. The magnetic field vector for this wave is: H = Hy uy. Use Maxwell’s equations to determine the corresponding electric field vector.
Ans) I've pretty much forgotten all this stuff from 1st year, so I'm not sure if my answer is correct.
\( \bigtriangledown \times H = \varepsilon_0 \frac{\partial E}{\partial t}\), \(H = (0, Hy, 0)\)
\( \bigtriangledown \times H = \begin{vmatrix} \hat{u}x & \hat{u}y & \hat{u}z \\ \frac{\partial}{\partial x} & \frac{\partial}{\partial y} & \frac{\partial}{\partial z} \\ 0 & Hy & 0 \end{vmatrix}\)
\(= \hat{u}x (\frac{-\partial Hy}{\partial z}) - \hat{u}y(0) + \hat{u}z (\frac{\partial Hy}{\partial z}) = (\frac{-\partial Hy}{\partial z}, 0, 0)\)
and
\(\varepsilon_0 \frac{\partial E}{\partial t}= (\varepsilon_0 \frac{\partial E}{\partial t}, 0, 0)\)
\( \Rightarrow \varepsilon_0 \frac{\partial E}{\partial t}= \frac{-\partial Hy}{\partial z} \)
Ans) I've pretty much forgotten all this stuff from 1st year, so I'm not sure if my answer is correct.
\( \bigtriangledown \times H = \varepsilon_0 \frac{\partial E}{\partial t}\), \(H = (0, Hy, 0)\)
\( \bigtriangledown \times H = \begin{vmatrix} \hat{u}x & \hat{u}y & \hat{u}z \\ \frac{\partial}{\partial x} & \frac{\partial}{\partial y} & \frac{\partial}{\partial z} \\ 0 & Hy & 0 \end{vmatrix}\)
\(= \hat{u}x (\frac{-\partial Hy}{\partial z}) - \hat{u}y(0) + \hat{u}z (\frac{\partial Hy}{\partial z}) = (\frac{-\partial Hy}{\partial z}, 0, 0)\)
and
\(\varepsilon_0 \frac{\partial E}{\partial t}= (\varepsilon_0 \frac{\partial E}{\partial t}, 0, 0)\)
\( \Rightarrow \varepsilon_0 \frac{\partial E}{\partial t}= \frac{-\partial Hy}{\partial z} \)