I can see that the laplace of f(t) = (2t) = (1/2)*(1/(s/2)^2) = 2/s^2

but I'm stumped at what I do with the 4... I see nothing like it on the laplace transform table... matlab gives the laplace of (t+4), a broken down version, to be 1/s^2 + 4/s. Again I see the 1/s^2 part from the t, but I don't se how they get 4/s for the 4 part... the laplace of u(t) is 1/t, is this why? Some explanation would be appreciated, thanks.