So I'm trying to figure out a way to handle a very large number of lithium or NiCd, NiMH daily (500-5000+ daily) where they need to be completely drained of energy so they don't pose a fire risk.
I'd like to be able to just connect to the battery pack that is 6v up to 60v but some of these packs read zero v due to a broken connection or a bad cell, so many cells are still fully (or nearly) fully charged but the pack can't be drained due to internal issues. So the only thing I can think of is for breaking the packs up and handling the batteries individually. It is possible to separate them by their type/size/voltage (3.6v Li-ion, 3.3v Li-ion, 1.2v NiCd or NiMH, 6 -12v Lead acid's, etc)
I was trying to think of the best way to manage the power from these cells and IDK if it would be worth it to try to capture it into a system which makes it usable or just dump it through a resistive load like a water heater, but IDK how to manage the the wide swing of V that would happen and potential of a massive amount of amperage available when new cells are placed in the "device"/drainer.
I'm thinking that I could make use of large amounts of hot water or even hot air (like a clothes dryer, heat guns - with the only limitation being not to exceed upper limit temps) - hot water is needed for washing some things and then hot air (and fans) for drying the materials.
I was thinking of using something like a 120v/240v resistance coil/heater and then running batteries in series (say 100 1.2v for 120v). The coil would reach full heat (as long as amperage is met, IDK what happens if it can't produce enough, maybe just limit resistor to utilize 1-2A) and then drop in heat as the cells loose charge but if one drops to zero, will it break the circuit or increase resistance creating a fire hazard?
IDK if this is the best method for draining the batteries, if anyone has any better ideas I'm open to it and would like to hear if my ideas of using resistive load to drain is adequate.
I originally thought the Joule thief might be interesting if I wanted to use the batteries to do something that needs a more constant V, but looking at the big picture, finding the most cost effective solution is probably the most important issue and like I said, I would need hot water & a method of drying materials, so maybe the resistive load is best.
I'd like to be able to just connect to the battery pack that is 6v up to 60v but some of these packs read zero v due to a broken connection or a bad cell, so many cells are still fully (or nearly) fully charged but the pack can't be drained due to internal issues. So the only thing I can think of is for breaking the packs up and handling the batteries individually. It is possible to separate them by their type/size/voltage (3.6v Li-ion, 3.3v Li-ion, 1.2v NiCd or NiMH, 6 -12v Lead acid's, etc)
I was trying to think of the best way to manage the power from these cells and IDK if it would be worth it to try to capture it into a system which makes it usable or just dump it through a resistive load like a water heater, but IDK how to manage the the wide swing of V that would happen and potential of a massive amount of amperage available when new cells are placed in the "device"/drainer.
I'm thinking that I could make use of large amounts of hot water or even hot air (like a clothes dryer, heat guns - with the only limitation being not to exceed upper limit temps) - hot water is needed for washing some things and then hot air (and fans) for drying the materials.
I was thinking of using something like a 120v/240v resistance coil/heater and then running batteries in series (say 100 1.2v for 120v). The coil would reach full heat (as long as amperage is met, IDK what happens if it can't produce enough, maybe just limit resistor to utilize 1-2A) and then drop in heat as the cells loose charge but if one drops to zero, will it break the circuit or increase resistance creating a fire hazard?
IDK if this is the best method for draining the batteries, if anyone has any better ideas I'm open to it and would like to hear if my ideas of using resistive load to drain is adequate.
I originally thought the Joule thief might be interesting if I wanted to use the batteries to do something that needs a more constant V, but looking at the big picture, finding the most cost effective solution is probably the most important issue and like I said, I would need hot water & a method of drying materials, so maybe the resistive load is best.