Hi, Im a new electronics hobbyist! One major problem I have stumbled upon is the idea of how electricity takes the least path of resistance. If 2 paths are presented then the path with least resistance will be taken by the electrons, while the higher resistance path will get only a minuscule amount of current. Yet, I dont understand the reasoning behind my diagram. If it is correct, then shouldnt current(a decent amount) flow only through the black wire? How come one green wire only gets 0.00001 amps, while the other gets 2amps? Shouldnt it be 0.000002 also? How do they differ from one and another?
"the path of least resistance" assumes limited "amps". In your diagram, unlimited amps are implied. Amps will flow in each circuit independent of the other. Limited by respective resistance to flow.
I'm sorry, but I dont quite follow what you just said. Im just a giant noob! could you post a corrected version of my diagram, or use laymans terms? Thanks for the help
Because you are showing a short across one of the the 10Ω resistors. The only resistance in parallel with that 10Ω resistor is that of the wire which is practically zero.
Okay, so there are 2 green wires Both have 10 ohm resistors The one on the top right gets almost no current because it is parallel with a wire, which has no resistance. As such, current prefers the wire a lot more. The other green wire, on the left, gets current, despite having the same amount of resistance. This is because it is parallel with the black circuit, which has 5 ohms. The difference between the two aren't so big as like the first case, so the green circuit on the left gets 2 amps while the circuit on the top right gets 0.00001 amps. Am I Right?
Tthe current is proportional to resistance for a fixed voltage as in your diagram. So you are correct in that the 10Ω leg gets 2A and the 5Ω leg gets 4A. The other shorted resistor basically sees no current flow because the short is effectively 0 resistance.
the path os least resistance dosnt get the current, all the current is shared in a ratio of resistances. thats why the upper 10 ohm resistor has a little current, in the ratio of the resistance of the shorting wire and 10 ohms of the resistor. while the 5 ohm reisitor is in series and all the current for the branch on the right flows through it. the shorting wire has a little resistance.
Diagram seems ok to me, Amps is analogous to water flow thru pipes. If you have a limited water supply, then your statement makes sense. The water will take the path of least resistance. Some paths may have near zero flow. However, with an unlimited supply, (diagram suggests no limit) all paths will see flow rates (amps) in proportion to restrictions. (ohms) The only reason I even mention this is to bring some truth to a statement that is misleading at best.
hey guys would this rendition of the amps within a parallel circuit be correct? e.g. the red amps would be found along the red wire thanks a bunch
Yes. The currents are correct. And just a side note, you are using the word amp as if it were a physical object. An amp is a unit of measurement, namely, speed. You are trying to describe current.