You can put any reasonable amount of capacitance you like on there to filter it!
It will work.... sort of. Why don't you try it? Put say 10uF 40V across the +/- of the bridge and scope it, you will find a very nice clean DC voltage.
That's all well and good but if you add a load, say a 4K7 resistor, scope it and see what happens.
What you are seeing is the effect of the load, it's trying to drag the voltage down.
Then we must add sufficient capacitance to maintain the voltage at a usable level.
Which "usable level", well from the data-sheet we can see that our voltage regulator needs 2.5V more on the input than on the output. (This is called the drop out voltage)
And since your output voltage needs to be 16V, then we must keep the input voltage at least 18.5V.
Now we have what we need to calculate the capacitor:-
C=0.7*I / (ΔV*f)
C=0.7*10 / (3*100)
C=0.023333 or 23,000uF
Wow that's a lot of capacitance!
It will work.... sort of. Why don't you try it? Put say 10uF 40V across the +/- of the bridge and scope it, you will find a very nice clean DC voltage.
That's all well and good but if you add a load, say a 4K7 resistor, scope it and see what happens.
What you are seeing is the effect of the load, it's trying to drag the voltage down.
Then we must add sufficient capacitance to maintain the voltage at a usable level.
Which "usable level", well from the data-sheet we can see that our voltage regulator needs 2.5V more on the input than on the output. (This is called the drop out voltage)
And since your output voltage needs to be 16V, then we must keep the input voltage at least 18.5V.
Now we have what we need to calculate the capacitor:-
C=0.7*I / (ΔV*f)
C=0.7*10 / (3*100)
C=0.023333 or 23,000uF
Wow that's a lot of capacitance!