Hello and thanks for taking the time to read and respond. I am in the process of restoring an old RF amp I recently changed the caps in the filter section and now replaced the HV diodes in the power suppy from single 3kv the a string on 1n4007. I have read that to equlize the voltage drop accross the diodes I need to add a cap and resistor in paralle accross each diode in series. My question is does anybody have the formula for finding the value of the resistor needed. Thanks

 

In that case, you must use a very high value resistors in paralel. Capacitors won't be needed. There are no formulas, but if you know the reverse resistance of a diode (or the reverse leakage current), then its resistor must have 20 times smaller resistance (or to be biased by a 20 times greater current). I think 10MOhms should do it. I expect a diode to have more than that.