I HAVE NO IDEA, NOT WITHOUT KNOWING WHAT THE CIRCUIT DOES OR WHAT YOU ARE TRYING TO DO!Originally posted by isha@Oct 26 2005, 03:54 PM
WHAT WILL BE THE VALUE OF RESISTANCE Rs
[ WHICH IS IN SERIES COMBINATION WITH DIODE IN4007 ]
SUCH THAT DIODE OPERATES SAFELY.
[post=11248]Quoted post[/post]
Can you be a bit more specific, because a diode's safety depends on the current flowing through it. Where does Rs come in?Originally posted by isha@Oct 26 2005, 03:54 PM
WHAT WILL BE THE VALUE OF RESISTANCE Rs
[ WHICH IS IN SERIES COMBINATION WITH DIODE IN4007 ]
SUCH THAT DIODE OPERATES SAFELY.
[post=11248]Quoted post[/post]
As said before you need to supply more info.Originally posted by isha@Oct 26 2005, 05:54 PM
WHAT WILL BE THE VALUE OF RESISTANCE Rs
[ WHICH IS IN SERIES COMBINATION WITH DIODE IN4007 ]
SUCH THAT DIODE OPERATES SAFELY.
[post=11248]Quoted post[/post]
It depends on the voltage and internal resistance of your source. The limiting thing is the current through the diode must not exceed its maximum rating.Originally posted by isha@Oct 27 2005, 02:01 AM
in parallel clipper circuit whose input is ac signal and output is taken across diode
what are limiting value of Rs [ range of resistance] such that diode can operate
normally.[safely]
is it enough????
[post=11272]Quoted post[/post]
YESOriginally posted by pebe@Oct 27 2005, 06:30 AM
It depends on the voltage and internal resistance of your source. The limiting thing is the current through the diode must not exceed its maximum rating.
The available voltage (Va) will be Vsource max - 0.7V
The resistance in circuit (Rc) will be source resistance of your signal + the resistor you fit.
The current will be Va/Rc
As the diode will only conduct every half cycle, you could probably double the maximum current allowed.
Does that help?
[post=11285]Quoted post[/post]
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