I have (what I presume is) a pretty basic question. I'm working on the attached problem and I know that when Vin is -5V, Db is ON and therefore Vx is -4.4V and Dx is off, so the output Vout is -2V. I also know that when Vin is 0V, Db is still ON and Vx is now 0.6V and Dx is now ON and Vout is 0V.
My question is about that point in between where the diode Dx turns ON. The diode should turn ON when Vx becomes greater than -2V, because there will be a more positive charge on the anode of the diode. So this will occur when Vin = -2.6V (which makes Vx = -2V). My question then is what is Vout at this point? There would still be a 0.6V drop across the diode, making Vout = -2.6V, correct? Would the graph of Vout vs Vin which the problem is looking for be what I have attached??
On a side note: is there a way to simulate an ideal diode in Microcap 9?
Thanks as always!
My question is about that point in between where the diode Dx turns ON. The diode should turn ON when Vx becomes greater than -2V, because there will be a more positive charge on the anode of the diode. So this will occur when Vin = -2.6V (which makes Vx = -2V). My question then is what is Vout at this point? There would still be a 0.6V drop across the diode, making Vout = -2.6V, correct? Would the graph of Vout vs Vin which the problem is looking for be what I have attached??
On a side note: is there a way to simulate an ideal diode in Microcap 9?
Thanks as always!
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