I need help trying to solve this diode problem
This is a large current device whose reverse leakage is reasonably independent of voltage. If Voltage at the resistor is 1V at 20 degrees Celsius, find the voltage of the resistor at 40 degrees Celsius.
(excuse the bad picture)
At first, I tried to solve for Is. But in order to do that, I needed to find the current flowing through the diode
i=V/R=>1V/(1*10^6)=1*10^-6 A,
but I'm totally lost from there. I tried using Is=i*e^(-V/vt) but I realized that the diode should be in reverse bias mode (i=-Is).
The answer came out to be 4V
This is a large current device whose reverse leakage is reasonably independent of voltage. If Voltage at the resistor is 1V at 20 degrees Celsius, find the voltage of the resistor at 40 degrees Celsius.
(excuse the bad picture)
At first, I tried to solve for Is. But in order to do that, I needed to find the current flowing through the diode
i=V/R=>1V/(1*10^6)=1*10^-6 A,
but I'm totally lost from there. I tried using Is=i*e^(-V/vt) but I realized that the diode should be in reverse bias mode (i=-Is).
The answer came out to be 4V