Does the 4069 inverter have more hysteresis than a Schmitt trigger?

I'm thinking about building a ring tester for inductors, in particular a TV flyback transformer. There's a nicely documented schematic here that uses a 4069 hex inverter IC to make an oscillator and perform other functions. (That schematic is an updated version of the original.)

I happen to have a pile of MC14584B hex Schmitt triggers and I think I can use one to replace the inverter 4069 in that schematic. Is there any reason to think it won't work?

I understand the hysteresis provided by a Schmitt trigger but the 4069 datasheet is confusing me: The "on" and "off" voltages seem farther apart than for the Schmitt trigger. Does the 4069 really have more hysteresis than the Schmitt trigger? I'm guessing I'm not reading the datasheet correctly.

 

The 4069 has no hysteresis. You are reading the datasheet incorrectly.
The hysteresis for MC14584B is 0.6V

 

You are reading the datasheet incorrectly.

No surprise there. Do I get credit for trying?

So, I think a little hysteresis in that circuit could be a good thing, maybe an improvement even. It should at least work?

Here's the circuit. The IC cut off on the upper right is a 4015 shift register to light up LEDs like a bar graph.

 

Try it. What is there to lose?

 

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I understand the hysteresis provided by a Schmitt trigger but the 4069 datasheet is confusing me: The "on" and "off" voltages seem farther apart than for the Schmitt trigger. Does the 4069 really have more hysteresis than the Schmitt trigger? I'm guessing I'm not reading the datasheet correctly.

The ON and OFF voltages are manufacturing tolerance limits for different devices, not the value for a single device. Any particular device will have a switch point somewhere between the tolerance limits with the ON and OFF transition voltages being very close (probably less than a tenth of a volt difference).

 

Got it. So when it says the on and off are, say, >2 and <8 for a 10V supply, it doesn't mean those would ever apply to the same piece.

 

Correct. In essence, the data sheet is saying that if you pick a random part and operate it within the specified conditions, that any voltage less than 2V will be seen and acted upon as a LO input while any voltage greater than 8V will be seen as a HI input. For voltages inbetween, it will be one or the other but different parts may make different decisions.