determine v0 #2

Discussion in 'Homework Help' started by qwerty321, Oct 25, 2008.

Oct 22, 2008
14
0
Hello..well i have the figure above and i need to determine V0..
i am using source transformation but at the end,i am ending up with two variables (Io and VO)
so i think i need a way to get I0 but how?
and if i use the node voltage analysis i end up with the same thing
help pelase
thank you

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2. mik3 Senior Member

Feb 4, 2008
4,846
70
Just apply KCL to the two nodes at top of the circuit and solve the unknowns with simultaneous equations. Finally, Io equals I through R3

3. alwayslearning Member

Feb 27, 2008
22
0
I would suggest using thevenin; remove the 2 ohm load-find Rth.

Then use the superposition Theroem to find Vth; which will be in terms of a constant plus 3*Io.

Then attach your 2 ohm load and solve for Vo using the voltage divider princible.

Then Io=Vo/Ro=...

Solve for Io?

Finally Vo=Io*2 ohms

4. hgmjr Retired Moderator

Jan 28, 2005
9,029
219
Greetings qwert123,

Have you been able to get any further along with your analysis of the problem you posted?

hgmjr

5. Ratch New Member

Mar 20, 2007
1,068
4
qwerty321,

Although we can get Io directly by node analysis, let's try something different. Like using a supermesh instead.

Designate the loop currents I1,I2, and I3 from left to right. Make a supermesh by mentally erasing the dependent current source, but remembering its effects. Then the equations of the two loops are:

24 -2*I1-2*I2 -4*(I2-I3) -12 = 0, and 12 -4*(I3-I2) -(2+2)*I3 = 0

And the equation for the dependent source, I1 -I2 = -3*I3

Three equations and three unknowns are solved to be I1,I2 and I3 = -9,9,and 6 respectively. So the dependent current source of 18 amps splits at the top with 9 amps going left, and 9 amps going right, and 6 amps going through R4.

Ratch

6. JoeJester AAC Fanatic!

Apr 26, 2005
4,074
1,776
Do you know R4 is shorted with a jumper in your diagram?