"bar A*B bar" or "/(A/B)" or "not A B bar" are different ways to describe the function you are talking about.Originally posted by Xander@Dec 13 2005, 03:33 PM
i need to apply DeMorgans law onto this boolean algebra.
its A.B with 2 bars. one bar over the b and another bar over both of them.
i think it ends up in A + B with both nots but i cant prove it. anyone like to help? and take me through it please?
[post=12432]Quoted post[/post]
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by Gary Elinoff