# Delta Connected and Star Connected Load Questions

#### haseeb112

Joined Dec 7, 2009
2
hey can someone help me to work this out please,

Each phase of a delta connected load comprises a resistor of 50ohms and a capacitor of 50microFarads in series,
the three phase load is connected to a 440v rms, line voltage and 50Hz three phase delta connected supply, calculate:

a> the phase and line currents
b> the phase and line voltages
c> the power factor
d> the total true power (p)
e> the reactive power (Q)
f> the apparent power (S)

and then repeat again for star connection same load.

i tried to use the capacitor as a coil, but still could'nt do it, got me even more confused, plus i was'nt sure if i was to use 1/2.pi.f.l or just 2.pi.f.l

thanks

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#### mik3

Joined Feb 4, 2008
4,843
Calculate the capacitors reactance according the the capacitance and the line frequency. Find the total impedance for each phase and then the current through each phase. The rest is just formulas.

#### haseeb112

Joined Dec 7, 2009
2
Calculate the capacitors reactance according the the capacitance and the line frequency. Find the total impedance for each phase and then the current through each phase. The rest is just formulas.

?
can you tell me what forumlas i have to use for the first two questions for delta

#### mik3

Joined Feb 4, 2008
4,843
To find the impedance of the capacitor use:

Zc=-j/(2*pi*f*C)

the impedance of the resistor (Zr) is just its resistance

Then find the total phase impedance Zph=Zr+Zc

Then the phase voltage for the delta connection equals the line voltage. Thus divide the line voltage by the phase impedance to find the phase current (Iph).

The line current is Iph*sqrt(3)

#### GetDeviceInfo

Joined Jun 7, 2009
2,198
To find the impedance of the capacitor use:

Zc=-j/(2*pi*f*C)

the impedance of the resistor (Zr) is just its resistance

Then find the total phase impedance Zph=Zr+Zc
Unusual approach.

Xc = 1/(2*pi*f*c)
R = R

Zphase = sqrt(Xcsq + Rsq)

Iphase = Vphase/Zphase

In Delta Vphase = Vline, In Y Vphase = Vline/sqrt(3)
In Delta Iline = Iphase * sqrt(3), In Y Iphase = Iline

For the power triangle, pf = watts/VA. S and Q hold the same angular component as your impedance triangle.

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