Current source breaks conservation of energy

Status
Not open for further replies.

Thread Starter

crosbis2

Joined Dec 31, 1969
0
A photodiode is often described as a current source in photovoltaic mode. the formula for developing a voltage across a photodiode diode is V = S. P . R
V= v out
S= photodidoe responsivity with wavelength
P= laser/ light power
R= load resistor

What i can't understand is placing a 10k resistor as R instead of a 1k resistor will give me a 10 times increase in voltage. so for the same input light intensity I've just increased my output voltage.........great- but doesn't it violate conservation of energy, where is the catch?
 

Dave

Joined Nov 17, 2003
6,969
We make it possible for people to give feedback on the site anonymously. If you wish to ask a question please register. Thank you.

Dave
 
Status
Not open for further replies.
Top