You can do this with a good CMOS op-amp with femtoamp input bias current. A problem you will run into is noise...you have a finite number of electrons to measure, and they will produce "shot" noise which occurs due to the randomness of moving electrons. The amount of noise is proportional to the square root of the number of electrons.I NEED AN CURRENT MEASURING IC HAVING RANGE 0-8 MICROAMPERE.. CAN ANYONE HELP ME??
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+1You can do this with a good CMOS op-amp with femtoamp input bias current.
Ummm.....sensitivity of 65 to 185mV/A is a little low for his application...Here's a Hall Effect based IC on a breakout board. http://www.sparkfun.com/products/8882
No current sense resistor, and related voltage drop, necessary.
If you are referring to me, I need a little time.sir,
cud u jus look 2 ur stocks and get me the result pls..
?????????? (needed 10 to post this reply)sir,
cud u jus look 2 ur stocks and get me the result pls..
Are you in a hurry? Measuring such current pecisely is nothing simple, so you need to be more patient, also making other threads on the same topic will just make others loose interest in your problem.sir,
cud u jus look 2 ur stocks and get me the result pls..
Are you in a hurry? Measuring such current pecisely is nothing simple, so you need to be more patient, also making other threads on the same topic will just make others loose interest in your problem.
Please use proper English and ask questions that are easy to understand. Also don´t expect others to reply on the same day, we got our jobs and stuff and do this only because we want to.
You could maybe start by telling us what is a radiosonde and what interface it has.sorry sir.. i'm new to this.. i'm in a hurry as i need to complete a project work within a 30 days deadline.. i need to sense a current and need to interface it to the radiosonde..
You could maybe start by telling us what is a radiosonde and what interface it has.
by Aaron Carman
by Robert Keim