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Q) Suppose F is the c.d.f of the random variable X, then what is the c.d.f of Y=F(X);
The answer is F(y)=y; therefore f(y)=1; y is in [0,1]
f(y)= probability distribution funtion
but in calculating this i had to assume that F(X) is monotonic which might not be the case
The answer is F(y)=y; therefore f(y)=1; y is in [0,1]
f(y)= probability distribution funtion
but in calculating this i had to assume that F(X) is monotonic which might not be the case
