How do I get create a circuit with only NOR gates?

 

What happens if you break a signal and insert two inverters in series?

So what happens if you put an inverter at the output of one of your OR gates and another inverter at the corresponding input to the AND gate?

 

I designed the logic for an automatic machine to stack different shaped boxes of pet food on pallets using Nor gates (Norbits) back in 1966 because they were the only logic blocks available at that time.

First, write a truth table for the circuit you have, then use Nor gates to make it happen.
Remember:
A Nor inverts.
A high Nor input gives a low output. .
A Nor gate will And and invert two low inputs.
Have fun.
Keith

 

Welcome to AAC!

How do I get create a circuit with only NOR gates using the following diagram below? I'm only able to come up with a circuit with only NAND gates, but not NOR gates

Show us the circuit with NAND gates and explain how it was derived.

What theorems have you studied?

 

would this be a correct answer? for NOR gates

You should be telling us.

Why did you change the "topology" of the gates? If you wanted to avoid wire crossings, you could have put D above B. Neatness counts when drawing schematics:

Why are you inverting B and D when you already had the inverted signals available? What is the purpose of two consecutive inverters?

 

Only a little.
What about the rest of what dl324 said?

 

As others have mentioned, you already have the inverted input signals available.

 

I made a mistake just now and I have since corrected the diagram. Would this be a better solution?

You forgot to include the inversion on the outputs of the NOR gates:

 

Why do you have the !D and !B inverters?

 

Oh, I see! These 2 inverters also have to be removed, right?

View attachment 203039
Overall, it would look something like this:
View attachment 203040

No

 

Why are you making life difficult?

Start with the original logic.

(/B OR /D) AND (B OR C)

You only have a single AND gate to convert to OR gate. Use DeMorgan's Theorem.

I can draw the logic diagram if you need me to do that.

 

View attachment 203044
Like this?

Still wrong. You're still not writing the terms correctly.

 

would this be a correct answer? for NOR gates
View attachment 203028

This is A correct answer, but it is not the simplest.

If you have a signal that is followed by two inverters, what can you do with those inverters?

 

View attachment 203044
Like this?

At this time, it appears that you are throwing random gates at the problem without understanding why.

I was going to comment on the gates before the input to the last gate; the gate producing the output...

But MrChips has the best approach. Look at the original problem!

 

Start from scratch.

Here is your initial problem.
Do you know DeMorgan's Theorems?

 

Yes, I do. !B + !D = !(BD).
In this case, the diagram shows !(BD)(B+C), right?

No, no, no!
We are so blind that the eye cannot see.



Replace the AND gate in the circuit diagram with its DeMorgan equivalent.

 

(!B+!D)(B+C) = !BC+!DB+!DC = (!B+!C)+(!B+!D)+(!C+!D) = !B+!C+!D

Oh, for heaven's sake!

What is the DeMorgan equivalent of X AND Y?

 

(!B+!D)(B+C) = !BC+!DB+!DC = (!B+!C)+(!B+!D)+(!C+!D) = !B+!C+!D

Try to answer the question asked and not guess what it means or the next step.

 

!X OR !Y

Wrong!
Try again.

 

!X OR !Y

You omitted the last step.