I'm just looking for some clarification regarding the second loop of this circuit.
Using mesh current analysis, the answer gives the voltage across the j9 inductor as:
-j9 * (I1 - I2)
I would have thought it was:
-j9 * (I2 - I1)
Is it (I1 - I2) becuase it is a voltage rise as opposed to a voltage drop?
Any help appreciated!