Just plug your functions into the convolution integral and out pops the answer. What could be easier?help me guyz
You failed to post your attempts, so that indicates to me that you have done nothing to solve the problem.if you don't know whether I have attempted or not then keep shut,
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The idea of "passing through" is not a physical one, but instead is the idea of multiplying, shifting/sliding and adding/integrating. To see this graphically, go back to the page that BenjaminSweet recommended and use your mouse to draw your signals as best you can. Make sure that you make the heights, widths and shapes of the waveforms as close as possible to your example. Then use your mouse to slide one signal by the other, and you will see a graphical answer that is almost the answer to your problem. It will display all of the regions, shapes and kinks of the real answer.ok my question is that how I will pass x(t) through h(t) as x(t) has magnitude greater than h(t) ???
That is the exact question I tried to answer. Did you try what I suggested? Did you go back to the page and create your own signal with a high amplitude? If you do that, you will see how it is possible to pass a signal with a high amplitude by (not through) a low amplitude signal.my professor told me that in convolution we pass one signal from another, in fact convolution means multiplication. but my question about this problem is that how it is possible to pass a signal with high amplitude through a low amplitude signal