This exam question has stumped me too. A resistor is placed at the emitter of the common base-emitter junction instead of the collector. I was stumped.
For NPN transistor assume: Vbe = 0.6V when just on
Vbe = 0.7V Bf = 100 in active region
Vbe=0.75, Vce = 0.2V
Question : When Vin = 5V in fig Q4a, transistor is in active region
(i) Write equation to show relationship between Ib, Ic , Ie
(ii) Express Ic and Ie in terms of Ib
(iii) Hence determine Vo.
Here is my answer:
Ib + Ic = Ie
Ic=100Ib
Vo = 10-0.2 = 9.8V (obviously wrong)
Can someone guide me through?
Thanks.
For NPN transistor assume: Vbe = 0.6V when just on
Vbe = 0.7V Bf = 100 in active region
Vbe=0.75, Vce = 0.2V
Question : When Vin = 5V in fig Q4a, transistor is in active region
(i) Write equation to show relationship between Ib, Ic , Ie
(ii) Express Ic and Ie in terms of Ib
(iii) Hence determine Vo.
Here is my answer:
Ib + Ic = Ie
Ic=100Ib
Vo = 10-0.2 = 9.8V (obviously wrong)
Can someone guide me through?
Thanks.
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