colector voltage in Dc analisis

Thread Starter

mosfat

Joined Dec 8, 2013
4
i need to find the Vout voltage.
i know drain current of M1 is 5mA

i need to find the collector voltage in Q1
how to do that?

thanks
 

Attachments

WBahn

Joined Mar 31, 2012
30,058
You need to show YOUR best effort to work YOUR homework problem. That gives us a starting point for discussion as it allows us to see what you are grasping and what you are overlooking.
 

Thread Starter

mosfat

Joined Dec 8, 2013
4
its like a chane
my goal is to find Vout

my work:
it comes dows to finding the voltage on the collector of Q1
the voltage on the base of Q1 is 4
the voltage on the emiter is zero because its DC analises and the small signal is zero.
the problem is ,if emitter voltage and its in the active state
VB-VE=0.7
VE=4 (the voltage sorse bellow)
so VE cant be zero althogh its active state
 

WBahn

Joined Mar 31, 2012
30,058
its like a chane
my goal is to find Vout

my work:
it comes dows to finding the voltage on the collector of Q1
the voltage on the base of Q1 is 4
the voltage on the emiter is zero because its DC analises and the small signal is zero.
the problem is ,if emitter voltage and its in the active state
VB-VE=0.7
VE=4 (the voltage sorse bellow)
so VE cant be zero althogh its active state
Well, you seem to be struggling with the right things -- or at least realizing that you are struggling with the things where you are not going about it right.

Yes, the base of Q1 is Vb=4V.

But if the emitter is 0V, then you have a transistor with a 4V base-emitter voltage. At the very least this would have to be in hard saturation, if not well into the smoke-emitting region of operation.

Yes, if Q1 is in the active state, the Vb-Ve=0.7V (or close enough for our needs), but then on what basis do you say that Ve=4V. Think about this.

If Vb=4V and Ve=4V, then wouldn't Vb-Ve be 0V?

So try again. You are on the right track. One you have the correct Ve, then it should be a simple matter to find Ie for Q1. With Ie, you should be able to find Ic and, from there, Vc very quickly.
 
Top