I'm studying Clipper Circuits on Diodes and connecting them to ground for the purpose of clipping off part of a input signal. During the positive alternation while the diode is forward bias they say that since the Cathode is at ground potential(0V), the Anode cannot exceed (.7 Volts). Then they go on to say that the output is clipped at +.7 Volts when the input exceeds this value.
My question is why exactly is the clipping taken place? They say the Anode cannot exceed .7 Volts because of the ground, but how can there even be any voltage at all (.7V while clippling anything higher) when the Anode is at Zero Volts Potential/Ground.
I know that you need to over-come the .7 Volts of a diodes potential barrier before current begins to flow, so I was expecting the output to be nothing. But to my suprise there is +.7 Volts during the positive alternation.
Can someone please help/explain? All help is appreciated...
My question is why exactly is the clipping taken place? They say the Anode cannot exceed .7 Volts because of the ground, but how can there even be any voltage at all (.7V while clippling anything higher) when the Anode is at Zero Volts Potential/Ground.
I know that you need to over-come the .7 Volts of a diodes potential barrier before current begins to flow, so I was expecting the output to be nothing. But to my suprise there is +.7 Volts during the positive alternation.
Can someone please help/explain? All help is appreciated...