In a forward clamping circuit, during the negative cycle, the diode conducts and capacitor is charged to the peak value of 5 volts(assuming a 10V p-p source).
The diode drops 0.7V, so 4.3 V across the capacitor is stored.
My question is, the source is at it's peak value only for an instant. So for that instant in time, the KVL across the loop is satisfied. During all other time instants of the negative cycle the KVL is not satisfied since the voltage across the capacitor and diode together is 5V throughout the negative cycle( neglecting the short time it takes for the capacitor to regain it's lost charge). What am I missing?
Also, sources are generally considered to be the rms value. Or in this case 5/1.414 V . So shouldn't the capacitor charge only to this value?
The diode drops 0.7V, so 4.3 V across the capacitor is stored.
My question is, the source is at it's peak value only for an instant. So for that instant in time, the KVL across the loop is satisfied. During all other time instants of the negative cycle the KVL is not satisfied since the voltage across the capacitor and diode together is 5V throughout the negative cycle( neglecting the short time it takes for the capacitor to regain it's lost charge). What am I missing?
Also, sources are generally considered to be the rms value. Or in this case 5/1.414 V . So shouldn't the capacitor charge only to this value?